Relativistic uniform system is an ideal
physical system, in which mass density (or any other physical quantity) depends
on the Lorentz factor of the system’s particles, but is constant in the
reference frames associated with the moving particles.
Содержание
Difference from classical uniform system
In classical physics, the ideal uniform body
model is widely used, in which mass density is constant throughout the volume
of the body or is given as the volume-averaged quantity. This model simplifies
solution of physical problems and allows us to quickly estimate different
physical quantities. For example, the body mass is calculated by simply
multiplying the mass density by the body volume, which is easier than
integrating the density over the volume in case of dependence of the density on
coordinates. The disadvantage of the classical model is that the majority of
real physical systems are far from this ideal uniformity.
The use of the concept of relativistic uniform
system is based on the special theory of relativity (STR) and is the next step
towards a more precise description of physical systems. In STR particular
importance is given to invariant physical quantities, which can be calculated
in each inertial reference frame and are equal to the values that these
quantities have in the proper reference frame of the body. For example,
multiplication of invariant mass by four-velocity gives the four-momentum of
the body containing the invariant energy, and multiplication of corresponding
invariant quantities by four-velocity allows us in
the case of motion of solid point particles to find the
four-potentials of any vector fields and to develop their complete theory. [1]
Another example is that for determination of four-velocity or four-acceleration as a rule the operator
of proper-time-derivative is used instead of time derivative. Therefore,
the use of invariant mass density and charge density of moving particles that
make up the system does not only conform to principles of STR but also
significantly simplifies solution of relativistic equations of motion.
Field functions for bodies of spherical shape
Field equations are most easily solved in case
of spherical symmetry in the absence of general rotation of particles. In this
case all the physical quantities depend only on current radius, which starts at
the center of the sphere. Below are presented solutions of equations for
various fields within the framework of STR, including solutions for scalar
potentials, field strengths and solenoidal vectors. Due to the random motion of
the particles in the system, the vector field potentials become equal to zero.
This leads to zeroing of solenoidal vectors of fields, including magnetic field
and gravitational
torsion field.
Acceleration field
The four-potential of acceleration field includes the
scalar potential
and the vector potential
. Applying four-curl
to the four-potential gives acceleration
tensor
. In curved
spacetime acceleration field equation with the field sources is derived from
the principle of least action: [1]
This equation after expressing the acceleration
tensor in terms of four-potential turns into the
wave equation for finding the four-potential of acceleration field:
which, taking into account the calibration
condition of the four-potential , can
be transformed as follows:
where is the speed of light,
is acceleration field coefficient,
is mass four-current with the covariant
index,
is metric tensor,
is Ricci tensor,
is four-velocity,
is invariant mass density of particles in comoving
reference frames, which is the same for all the particles.
In Minkowski spacetime within the framework of
STR, covariant derivatives of the form turn into partial derivatives of the form
,
while the result of action of the partial derivatives does not depend on the
order of their action. As a consequence of calibration of the 4-potential, the equality holds:
. As a result, the four-potential of acceleration
field can be found from the wave equation:
This equation can be divided into two equations
– one for scalar potential and the other for vector potential of acceleration
field. In the system under consideration the vector potential is equal to zero,
and the scalar potential of acceleration field is given by:
where are time components of metric tensor,
is Lorentz factor of particles in the
reference frame K' associated with the
center of the sphere.
Since scalar potential of stationary system does
not depend on time, the wave equation for the scalar potential turns into the
Poisson equation: [2]
and the following formula is obtained for the
Lorentz factor of particles: [3]
where is Lorentz factor of particles at the center
of the sphere,
is current radius.
The acceleration field strength and corresponding
solenoidal vector are expressed by the formulas:
Pressure field
The four-potential of the pressure field includes the
scalar potential
and the vector potential
, and obeys the calibration condition:
.
The pressure field equation with the field
sources, pressure field
tensor and equation for finding the four-potential
of pressure field have the form: [1]
where is pressure field coefficient.
In STR the latter equation turns into the wave
equation:
In stationary case the potentials do not depend
on time and time component of the wave equation turns into the Poisson equation
for the scalar potential of the pressure field:
Solution of this equation inside the sphere with
particles is as follows: [3]
where is scalar potential at the center of the
sphere. This potential is approximately equal to: [4]
where acceleration
field constant and pressure field constant
are expressed by the formulas:
The strength of pressure field and corresponding
solenoidal vector are found as follows:
Gravitational field
The
gravitational
four-potential of gravitational field is made up with the
use of scalar
and vector
potentials. Calibration condition of the four-potential is:
.
The gravitational field equation with field
sources, the gravitational
tensor and the equation for finding the
four-potential of gravitational field in covariant theory of gravitation have the
form: [5] [6]
where is gravitational
constant.
In STR the latter equation is simplified and
becomes the wave equation:
From the wave equation in stationary case, the
Poisson equation follows for scalar potential inside the sphere with randomly
moving particles in the framework of Lorentz-invariant theory of gravitation (LITG):
The right-hand side of this equation contains Lorentz
factor ,
which depends on the radius according to (1). In addition, the internal scalar
potential near the surface of the sphere must coincide with the scalar
potential of external field of the system, in view of standard potential gauge,
that is with equality of potential to zero at infinity.
As a result, dependence of scalar potential on
the current radius differs from dependence in classical case of uniform sphere
with the radius and is equal to it only approximately: [3]
For
gravitational
field strength and gravitational torsion
field inside the sphere we obtain the following: [7]
Solutions for external gravitational field
potential and for field strength according to LITG are as follows:
Here, the auxiliary mass is equal to the product of mass density
by volume of the sphere:
.
From expressions for potential and strength of external gravitational field we
can see that the role of gravitational mass is played by the mass
Since
then the relation
is satisfied.
To
understand difference between these masses we should calculate total
relativistic mass of particles moving inside the sphere. For motion
of particles there should be some voids between them. Both the average
accelerations and average velocities of particles inside the sphere are
functions of current radius. Dividing the particles’ velocities by their
acceleration, we can find dependence of average period of oscillatory motion of
particles on the radius. Finally, multiplying the velocity by the average
period of motion, we can obtain an estimate of the size of voids between the
particles.
In
order to calculate volume of the sphere, it is necessary to sum up volumes of
all typical particles moving inside the sphere, as well as volumes of the voids
between them. Suppose now that the sizes of typical particles are much larger
than the voids between the particles, and volume of the voids is substantially
less than the total volume of particles. In this case, we can use approximation
of continuous medium, so that unit of mass of matter inside the sphere will be
given by approximate expression , where
is mass density in reference frames
associated with the particles,
is Lorentz factor of the moving particles,
the product
gives mass density of the particles from viewpoint
of an observer, who is stationary with respect to the sphere, and volume
element
inside the sphere corresponds to the volume
of the particle from the viewpoint of this observer.
This
leads to the fact that total volume of particles moving inside the sphere
becomes approximately equal to the volume of the sphere. For the mass, in view
of Lorentz factor (1), the following relation is obtained:
This implies equality of gravitational mass and total relativistic mass
of particles moving inside the sphere. The
both masses are greater than the mass
.
By the method of its calculation, the mass
is equal to the sum of invariant masses of particles
that make up the system.
The external gravitational torsion field is equal to
zero:
Electromagnetic field
The electromagnetic four-potential of electromagnetic field includes scalar
potential
and vector potential
.
The
covariant Lorentz calibration for four-potential is:
. For a fixed
uniformly charged spherical body with random motion of charges total
electromagnetic field on the average is purely electric and the vector
potential is equal to zero.
The electromagnetic field equation with the
field sources, electromagnetic tensor and equation for finding four-potential are
expressed as follows:
where is electric
constant,
is electromagnetic four-current.
The latter equation in STR turns into the wave
equation:
Due to the absence of time-dependence in the
case under consideration, the wave equation becomes the Poisson equation for scalar
potential inside the sphere:
where is charge density in the reference frames
associated with the charges.
Dependence of scalar potential on current radius
in general case differs from dependence in classical case of potential of a
uniformly charged sphere with the radius ,
coinciding with it only in the first approximation: [8]
Electric
field strength and magnetic field inside the sphere have the
form:
Outside the system under consideration charge density
is equal to zero and Poisson equation for scalar potential turns into Laplace
equation:
Solution for external electric field potential,
corresponding to potential gauge and Maxwell's equations for electric field
strength is given by:
External magnetic field is equal to zero:
In these expressions, the charge is an auxiliary quantity equal to the product
of charge density
by volume of the sphere:
.
In this case, the following quantity serves as total
charge of the system:
while The charge
is calculated in the same way as the mass
and has the meaning of the sum of charges of
all the system’s particles.
Tensor field invariants
The knowledge of field strengths and solenoidal
components of fields allows us to find tensor components of corresponding
fields with covariant indices. To pass on to the field tensors with contravariant
indices we need to know metric tensor. In STR the metric tensor does not depend
on coordinates and time, is uniquely defined, and in Cartesian coordinates
consists of zeros and unities. As a result, it is easy to find the tensor field
invariants ,
,
and
,
where
,
,
and
are the acceleration tensor,
the pressure field tensor,
the gravitational tensor and the
electromagnetic tensor, respectively.
The tensor field invariants are included in Lagrangian,
Hamiltonian. action function and relativistic energy of the system, and they
are located there inside integrals over space volume. In addition, they are
included in corresponding stress-energy tensors of the fields. [2] Since in the system under consideration the
solenoidal vectors are zero, the tensor invariants depend only on the field
strengths:
The volume integrals of tensor invariants
multiplied by corresponding factors were calculated in the article. [7] For acceleration field and pressure field the
integrals are taken only over volume of the sphere:
The gravitational and electromagnetic fields of
the system are present not only inside but also outside the sphere, where they
extend to infinity, while field strengths of internal and external fields
behave differently. The field strengths and
are substituted respectively into integrals
of tensor invariants of these fields taken over volume of the sphere, which
gives the following:
Into volume integrals of tensor invariants of gravitational
and electromagnetic fields of the system outside the sphere the field
strengths and
are substituted, respectively:
Energies of particles in field potentials
All the four fields act on particles inside the
sphere, and therefore each particle of the system acquires corresponding energy
in a particular field. The energy of a particle in a field is calculated as volume
integral of product of effective mass density
by corresponding scalar potential, and for electric
field the energy is determined as volume integral of product of effective
charge density
by scalar potential
, where Lorentz
factor
from (1) is used. In STR the energies of
particles in acceleration field, pressure field, gravitational and electric
fields in uniform relativistic spherical system, in view of expressions for the
field potentials [7] and corrections to calculations, [8] [9]
[10] [11] are, respectively:
Note
that all fields in which particles are located are not fields from external
sources, but are generated by the particles themselves. As a result, the
particles’ energies calculated above in scalar potentials of the fields are
twice as large as potential energy of one or another interaction. For example,
in order to calculate electrostatic energy of a system of two charges, it is
sufficient to take potential of first charge at location of second charge and
to multiply it by the value of the second charge. But if we use formula for energy
in the form of an integral, then the electrostatic energy will be taken into
account twice, because the term is added, which contains potential of second
charge at location of first charge multiplied by the value of the first charge. On the
other hand, the electrostatic energy must consist of two components that take
into account both the energy of particles in each other’s fields and the energy
of electric field itself.
Instead, in electrostatics, the
electrostatic energy is calculated either through the scalar potential or
through the field strength by integrating time component of stress-energy
tensor over volume. Both methods provide the same result, but the connection
between field energy and energy of particles in field potential is lost in this
case, and it is not clear why these energies should coincide.
Relation between field coefficients
For the four fields under consideration equation
of motion of matter in the concept of general field is as follows: [12]
[13]
where is mass four-current,
is electromagnetic four-current.
Components of field tensors are field strengths
and corresponding solenoidal vectors, but in the physical system under
consideration the latter are equal to zero. As a result, space component of the
equation of motion is reduced to the relation:
If we substitute here expression for field
strengths inside the sphere, we obtain relation between field coefficients: [14]
The same is obtained for time component of equation
of motion, which leads to generalized Poynting theorem. [9]
Relation between energies of internal and external fields
In article [15] it was found that energy
of particles in gravitational field inside stationary sphere is up to a sign
two times greater than total energy associated with tensor invariants of gravitational
field inside and outside the sphere. A similar situation takes place in the system under consideration with random
motion of particles and zero solenoidal vectors both for gravitational [10] and electromagnetic fields. [8] In particular, we can write the following:
These expressions relate the energy of particles
in scalar field potentials with the energy found with the help of field
strengths.
Relativistic energy
In curved spacetime the system’s energy for continuously
distributed matter is given by the formula: [2] [4]
This formula is valid in the case where it can
be assumed that potentials and field strengths at each point in space do not
have a direct dependence on the speeds of motion of individual particles of the
system.
In STR the metric tensor determinant is ,
the time component of four-velocity is
,
and in order to calculate the energy of spherical system with particles, taking
into account the fields’ energies, we can use the above-mentioned energies of
particles in field potentials and energies in the form of tensor invariants of
the fields:
The expression for energy is simplified if we
use the relation between field coefficients (2):
Taking into account relations between energies
of internal and external fields also simplifies expression for the system’s
energy:
Relation between energy and cosmological constant
In the approach under consideration, relativistic
energy of the system is not an absolute value and requires gauging. For this
purpose the cosmological constant is used. The gauge condition for the four
main fields is related to sum of products of the fields’ four-potentials by corresponding
four-currents and has the following form: [2] [4]
where for large cosmic systems , and
is a constant of order of unity.
Within the framework of STR gauge condition has
the following form:
If we divide the system’s particles and remove
them to infinity and leave there at rest, the terms with products of vector
field potentials by velocity of particles would vanish, and Lorentz factor of an
arbitrary particle would be
.
On the right-hand side we will have only the sum of terms specifying energy
density of particles located in potentials of their proper fields. Since
, we see that the cosmological constant for
each system’s particle is up to the multiplier
equal to rest energy density of this particle
with a certain addition from its proper fields. Then the integral over volume
of all the particles gives a certain energy:
where the gauge mass is related to gauge condition of the energy.
In the process of gravitational clustering the
particles that were initially far from each other are united into closely bound
systems, in which the field potentials increase manyfold. In the system under
consideration , solenoidal vectors of fields are considered
equal to zero due to random motion of particles, which gives the following:
Expression on the right-hand side is part of relativistic
energy of the
system, so that the energy can be written as follows:
The mass is related to relativistic energy of generally
stationary system and is the inertial mass of the system. In view of (2), the
energy will be equal to:
This shows that relativistic energy of this
system is equal to gauge mass-energy ,
from which the gravitational and electromagnetic energy of fields outside the
system should be subtracted.
Lagrange function and motion integrals
Lagrange function for a system of particles and
four main vector fields has the following form:[1] [2]
Here is scalar curvature. With the help of such
Lagrange function, one can calculate the generalized momentum of the system:[16]
This vector depends on vector potentials of all
four fields and is preserved in a closed physical system, that is, it is an
integral of motion. Another integral of motion is relativistic energy of the
system , which is found by formula (5). Further, it
is assumed that one can neglect the contributions from gravitational and
electromagnetic fields outside the matter and take into account only the
generalized momentum. Then we can assume that these values form a four-momentum
of the system, written with a covariant index:
The angular momentum of the system is also an
integral of motion:
The antisymmetric angular momentum pseudotensor
is determined through the four-radius , taken with a covariant index, and through
the four-momentum
:
The spatial components of the angular momentum
pseudotensor are the components of the angular momentum
of the system:
The radius-vector of the center of momentum of a
physical system is determined by the formula:
The time components of the pseudotensor are the components of the three-dimensional
vector
, which is often called the time-varying
dynamic mass moment:
If we take into account definition of radius-vector
of center of momentum and relationship between the momentum and velocity of the
center of momentum in the form , we get the relation:
In a closed system the pseudotensor must be conserved, and its components must be
some constants. For space components of the pseudotensor this results in
conservation of angular momentum:
. From equality of the pseudotensor’s time
components and components of the vector
it follows that it should be
.
Given the expression for
, it can be written as
, where the constant vector
specifies position of the system’s center of
momentum at
.
Thus, in this reference frame we obtain equation of motion of the center of
momentum at constant velocity
,
as a property of motion of a closed system.
The component
of angular momentum of a uniform ball, taking
into account relativistic corrections, can be calculated by the formula: [17]
Here is invariant mass density,
is angular velocity of rotation of the ball
having a radius
.
Integral vector
The equation used to find metric tensor
components in covariant
theory of gravitation for tensors with mixed indices has the
following form:[2]
here is Ricci tensor with mixed indices;
is unit tensor or Kronecker delta;
,
,
and
are stress-energy tensors of acceleration
field and pressure field, gravitational and electromagnetic fields,
respectively.
With the help of covariant derivative we can find four-divergence of both sides of
the above equation for metric. The divergence of the left-hand side is zero due
to equality to zero of divergence of t Einstein tensor,
, and also as a consequence of the fact that
outside the body the scalar curvature vanishes,
, and inside
the body it is constant. The latter follows from the gauge condition of energy
of closed system. The divergence of the right-hand side of equation for the
metric is also zero:
where the tensor
with mixed indices represents the sum of stress-energy
tensors of all fields acting in the system.
The resulting expression for tensors’ space
components is nothing but differential equation of matter’s motion under action
of forces generated by fields, which is written in a covariant form. [13] As
for the tensors’ time components, for them the expression is expression of generalized
Poynting theorem for all the fields. [9]
In a weak field and at low velocities of motion
of particles, the equation can be integrated over four-volume, taking
into account the divergence theorem. As a result, at the initial moment of time
for the system under consideration, the following relation will be valid:
In a closed system, the four-dimensional
integral vector must be constant. [16] For a stationary sphere with randomly moving
particles in continuous medium approximation, the energy fluxes of fields
defining the components
, where
, are missing , so that the spatial components
are zero,
. As for the time component
of integral vector, then for volume occupied
by matter inside the sphere, it also vanishes due to relation (4) for field
coefficients. However, outside the sphere, where there are only gravitational
and electromagnetic fields, the time component of integral vector is not equal
to zero. As a result, the contribution to this component is made by energies of
external fields:
It follows from the above that integral vector
shows distribution of energy and energy fluxes in the system under
consideration.
For the nonzero space components of integral vector to appear some stationary
motion of matter and fields is required, for example, general rotation, volume
pulsations or mixing of matter. In this case, solenoidal vectors and the
fields’ energy fluxes appear in the system.
Since the integral vector is associated with energies and energy fluxes
of fields in stress-energy tensors, it differs from the four-momentum
, which includes invariant mass and
proportional to its rest energy. It turns out that difference between
and
is due to fundamental difference between
particles and fields, they cannot be reduced to each other, although they are
interrelated with each other.
Virial theorem and kinetic energy of particles
In article [18] kinetic energy of particles
of the system under consideration is estimated by three methods: from virial
theorem, from relativistic definition of energy and using generalized momenta
and proper fields of the particles. In the limit of low velocities, all these
methods give for kinetic energy the following:
The possibility to use generalized momenta to
calculate the energy of particles’ motion is associated with the fact that
despite zeroing of vector potentials and solenoidal vectors on the large scale,
in volume of each randomly moving particle these potentials and vectors are not
equal to zero. As a result, the energy of motion of the system’s particles can
be found as the half-sum of scalar products of vector field potentials by the
particles’ momentum, while for electromagnetic field we should take not the
momentum, but the product of charge by velocity and Lorentz factor.
If we square the equation for in (1), we can obtain dependence of squared
velocity of particles’ random motion on current radius:
On the other hand, we can assume that where
denotes averaged velocity component directed
along the radius, and
is averaged velocity component perpendicular
to the current radius. In addition, from statistical considerations, it follows
that
This implies dependence of radial velocity on
the radius:
Next, from the virial theorem we find squared
velocity of particles at the center of the sphere:
This makes it possible to estimate the Lorentz
factor at the center:
In the ordinary interpretation of virial theorem
the time-averaged kinetic energy of a system of particles must be two times
less than averaged energy associated with the forces holding the particles at the
radius-vectors
:
However, in relativistic uniform system this
equation is changed:
while the quantity exceeds the kinetic energy of particles,
, and it becomes equal to it only in the limit
of low velocities.
In contrast to classical case, total time
derivative of virial in stationary system is other than zero due to the
virial’s dependence on the radius:
An analysis of integral theorem of generalized
virial makes it possible to find, on the basis of field theory, a formula for
the root-mean-square speed of typical particles of a system without using the
notion of temperature: [19]
Extreme objects
In formula (2) for gravitational field strength outside a
body there is a quantity
, where
. As was shown in
article, [11] at the value
radians
the gravitational field strength
vanishes
and gravitational acceleration disappears. Therefore, in real physical objects
the following condition must hold:
. If the angle
is
increased, then the quantity
would
first increase, and then would begin to decrease and even change its sign. So,
at
we have
, at
we have
, at
we have
.
Let us now consider the observable Universe, which on
a scale 100 Mpc or more can be considered as a relativistic uniform system. The
total mass-energy density of the Universe is close to the critical value kg/m3 and
the size of the Universe can be estimated as the Hubble length
m, where
is Hubble
parameter.
Using approximate equality according
to, [14] we find the value
radians. Since the
angle
is sufficiently large,
then for modeling of gravitational field of the Universe it is necessary to use
refined formulas with sines and cosines. For example, if we take the size of observable
Universe equal to
, then we have
, and gravitational
field at t boundaries of the Universe will tend to zero. This is what we
observe in the form of a large-scale cellular structure consisting of clusters
of galaxies. The reason for the gravitation action weakening is assumed to be
graviton scattering by the particles of space medium. [20]
Another extreme object is a proton, in which mass
density in entire volume changes approximately by 1.5 times. As a result, in
the first approximation a proton is a relativistic uniform system. The proton
radius is of the
order of 0.873 fm, [21] and average
density is of the order of
kg/m3.
As a gravitational constant at the atomic level the strong gravitational constant
should be
used. An estimate of the quantity
for a
proton at
gives:
radians. This shows
that a proton is an extreme object from the point of view of weakening of its
gravitational field.
In article, [11] a method
is provided for estimating Lorentz factor of matter’s motion at the center of a
proton, which gives . In addition, radius of
action of strong
gravitation in matter with the critical mass density
kg/m3 in
observable Universe is estimated:
m. On a
large scale in the Universe not the strong gravitation, but the ordinary
gravitation is acting with the radius of action of the order of Hubble length.
Let us suppose that
corresponds to radius of a certain black hole for strong gravitation, calculated by the
Schwarzschild formula:
. If the mass
is
, then for radius of a black hole with such
mass we obtain
m, and mass is
kg. The Schwarzschild
formula admits a black hole for strong gravitation at small mass of the order
of proton mass, large mass density and a radius smaller than the proton radius.
In addition, substitution of the mass
and the
radius
into Schwarzschild
formula formally corresponds to a black hole with a large radius and low
density
. However, for an external
observer, such a black hole would rather correspond not to a black hole, but to
an object, containing strongly rarefied hydrogen gas of cosmic space.
Similarly, the Metagalaxy with the radius of order of
and mass
density
is not a black hole,
although it corresponds to the Schwarzschild formula for ordinary gravitation.
Hence, in accordance with the theory of infinite
nesting of matter, conclusion follows – at each level of matter corresponding
gravitation forms only one type of the most compact and stable object. So, at
the level of nucleons a proton appears under the action of strong gravitation,
and at the level of stars the ordinary gravitation generates a neutron star. If
we multiply the radius of a neutron star by coefficient of similarity in size
, which is
equal to the ratio of stellar radius to the proton radius, we obtain radius of
the order of
m. This radius must
correspond to a compact object of a neutron star-type at the level of
metagalaxies, which can emerge under the action of gravitation at this matter
level. In the first approximation, the gravitational constant for metagalaxies is
determined with the help of the similarity theory:
m3•s–2•kg–1,
where
is coefficient
of similarity in velocities,
is coefficient of similarity in mass.
By analogy with the case of a proton, a neutron star
is also considered as a relativistic uniform system. For a star with the mass
of 1.35 Solar masses, the radius km and average
density
kg/m3,
at
we obtain
the angle
radians. With this in
mind, if we substitute into (3) the stellar mass instead of
and the
stellar radius instead of
, we can
estimate Lorentz factor at the center of the star:
. This allows us to estimate temperature at
the center of the star:
K, which
is close enough to calculation of temperature at the center of a newly formed
star. [14]
Thus, dependences of gravitational field inside and
outside bodies in article [11] are in
good agreement with conclusions of Le Sage’s theory of gravitation and the theory of Infinite
Hierarchical Nesting of Matter, with strong gravitation at the level of nucleons and
with the concept
of a dynamic force field in electrogravitational
vacuum.
Cosmological constant and scalar
curvature
According to
(6), outside a body, where the four-currents are equal to zero, cosmological
constant becomes equal to zero. In addition, scalar
curvature
also becomes equal to zero. [4] Inside the body the relation
holds true, so that in matter with higher
density both the scalar curvature and the cosmological constant increase. These
quantities can be calculated using (6) as averaged values for typical particles
of physical system. For cosmic space we obtain approximately the following:
m-2, where the average mass density
is
kg/m3.
A similar
formula for a proton gives the following: m-2. However, for a
proton in the calculations we should use the strong gravitational constant
. In this case, we find:
m-2. The obtained value is almost 84
orders of magnitude greater than the value of cosmological constant for cosmic
space. The difference between cosmological constants for cosmic space and for a
proton is associated with averaging procedure: the cosmological constant inside
a proton is large, but in cosmic space matter containing protons, neutrons and
electrons is very rarefied, the main place is occupied by void, so that cosmological
constant averaged over entire space becomes a small value. Thus one of the
paradoxes of general theory of relativity is solved, in which the cosmological
constant is associated with zero vacuum energy and therefore it must be very
large, but in fact the cosmological constant turns out to be a small value.
For relativistic
uniform system with four fields acting in it, average value of cosmological constant in matter is
constant and can be written as follows:
This expression
can be simplified by using scalar potential of gravitational field and scalar potential of electric field
on surface of body at
:
Field energy theorem
In a
relativistic uniform system, the exact values of strengths and potentials of
all active fields are known. This allows us to check the field energy theorem for such a
system and verify the theorem.[22] This theorem explains, in particular,
why electrostatic energy can be calculated either through the field strength,
included in the electromagnetic field tensor, or in another way, through the
field potential.
The kinetic energy and potential energy of electromagnetic field are defined as follows:
If we take entire infinite volume both inside and outside matter of the
system, then in the framework of special theory of relativity and in the
absence of magnetic fields, these expressions are simplified:
By virtue of the field energy theorem, the following relation will be
satisfied:
In general case, tensor invariant is expressed in terms of square of electric
field strength and square of magnetic field induction: . The field energy density is found through
the time component of stress-energy tensor:
.
In electrostatics, when there are no magnetic fields and ,
volume integral
of tensor
invariant becomes proportional to volume integral of the component
. As a result, electrostatic
energy can be calculated in different ways:
Besides:
Binding energy
With the help of covariant theory of gravitation total energy, binding
energy, energy of fields, pressure energy and potential energy of a system
consisting of particles and four fields is precisely calculated in the
relativistic uniform model. [23] A noticeable
difference is shown between the obtained results and relations for simple
systems in classical mechanics, in which the acceleration field and pressure
field are not taken into account or the pressure is considered to be a simple
scalar quantity. In this case the inertial mass of a massive system is less
than the total inertial mass of the system’s parts.
System mass
The article [24]
shows that relativistic uniform system with continuous matter distribution is
characterized by five types of mass: the gauge mass is related to cosmological constant and
represents mass-energy of matter’s particles in four-potentials of the system’s
fields; the inertial mass
;
the auxiliary mass
is equal to product of the particles’ mass
density by volume of the system; the mass
is the sum of invariant masses (rest masses)
of the system’s particles, which is equal in value to gravitational mass
. The relation for these masses is as follows:
Solution of 4/3 problem
For the electromagnetic and gravitational fields, the 4/3 problem consists
in inequality of mass-energy extracted from the energy of field of a body at
rest, and mass-energy resulting from the field momentum of the moving body. If
such a body is a relativistic uniform system of spherical shape, then mass-energy
associated with electrostatic energy of the system is:
The energy flux of electromagnetic field of a moving sphere is
calculated using the Poynting vector. Let be Lorentz factor, and
be velocity of the sphere. Having calculated energy fluxes of the
field inside and outside the sphere, as well as total energy flux, we can find corresponding
quantities with dimension of momentum associated with these energy fluxes: [9]
From here we find the mass-energy associated with the field energy fluxes:
For mass-energies, a ratio describing the 4/3 problem is obtained:
If we consider the energy and energy flux of electromagnetic field only
inside the sphere, or only outside the sphere, similar correlations are
obtained for corresponding mass-energies.
As indicated in the article, [9]
the mass-energy mismatch is a consequence of the fact that time
components of electromagnetic stress-energy tensor and their integrals over
volume do not together form any four-vector. In contrast, four-momentum of a
system is a four-vector, so that the same inertial mass enters both the energy
and momentum of the system. On the other hand, energy and momentum of electromagnetic
field are included only as components in energy and momentum of entire system
under consideration, and therefore they themselves do not have to form a
four-vector.
To calculate a four-momentum of the system, it is necessary to add energy
and momentum of other fields operating in the system to the energy and momentum
of electromagnetic field. In addition to electromagnetic field, the minimum set
of fields of the system includes acceleration field, pressure field and gravitational
field, and therefore it is necessary to take into account their energy and
momentum. In this case, inside the sphere, the sum of energies of all fields
found through tensor invariants and through stress-energy tensors is zeroed
out. The total energy flux and total momentum of fields inside the sphere are also zero, so that
within the sphere, the 4/3 problem as applied to general field disappears.
The equality to zero of sum of energies and sum of momenta of fields inside the
sphere with randomly moving particles is a consequence of the fact that particles
and fields have the opportunity to exchange energy and momentum with each
other. As a result, contribution to relativistic energy of the system is made
only by particle energies in scalar potentials of fields, and energies of electromagnetic
and gravitational fields outside the sphere.
The 4/3 problem shows in particular why energy and momentum of an electron
and any other body cannot be reduced only to action of its own electromagnetic
field. Despite the fact that an electron has a maximum charge per unit mass and
is extremely charged, there are other fields in the electron's matter, for
example strong gravitation. These
fields have their own energy and momentum, which contribute to four-momentum of
the electron.
Relations between field
potentials
In the
article, [25] a connection was found between scalar potentials of acceleration
field and pressure field in relativistic uniform system:
In addition,
a relativistic expression for pressure was found:
where is mass density of moving matter,
is speed of light,
is Lorentz factor.
In the limit
of low velocities, this relationship turns into standard formula of kinetic
theory of gases.
Metric inside and outside system
Standard
expression for square of interval between two close points in metric theories
is the following:
For static
metric with spherical coordinates
there are
four nonzero components of the metric tensor:
and
As a
result, there is
As it was
found for components of metric inside a spherical body within the framework of relativistic
uniform model, [26] and
where is gravitational
constant;
is a
coefficient to be determined;
is radial
coordinate;
is the
speed of light;
is invariant
mass density of matter particles;
is Lorentz
factor of particles moving at the center of body;
is gravitational
potential at the surface of sphere with radius
and
gravitational mass
;
quantities
and
are auxiliary
values;
is invariant
charge density of matter particles, moving inside the body;
is electric
scalar potential at the surface of sphere with total charge
;
is potential
of pressure field at the center of body.
On surface
of the body, with , the component
of metric
tensor inside the body must be equal to the component
of metric
tensor outside the body. This allows us to refine expression for metric tensor
components outside the body:
where is gravitational
potential outside the body;
is electric
potential outside the body.
Generalized four-momentum and total four-momentum
In the paper, [27] formulas
were found for calculating generalized four-momentum of a physical system in
curved space-time taking into account contribution from particles and fields of
the system. A differential four-dimensional Euler-Lagrange equation for
continuously distributed matter was also obtained. Both the formulas for generalized
four-momentum and Euler-Lagrange equation are satisfied in relativistic uniform
system. In the paper, [28] covariant formulas for relativistic four-momentum of a
physical system were derived, which were also verified in a relativistic
uniform system. It was shown that four-momentum is expressed by the sum of two
four-vectors of integral type with covariant indices, one of these four-vectors
is generalized four-momentum of the system, and the other four-vector describes
four-momentum of fields of the system. Additionally, the 4/3 problem and
interpretation of integral vector found by integrating over volume of time
components of stress-energy tensor of the system were considered. The fact that integral
vector cannot be four-momentum of the system, as is assumed in general theory
of relativity, is confirmed by direct calculation and follows from the fact
that a four-vector cannot be obtained from tensor components. Similarly, volume
integral of time components of stress-energy tensor of electromagnetic field does not yield four-momentum
of electromagnetic field, but an integral vector that is not a four-vector. As
a consequence, the mass-energies contained in components of integral vector are
not equal to each other and are related in the proportion 4/3.
Covariant formulas for four-momentum were used to determine the
components of angular momentum tensor of a physical system in the article. [29]
References
See
also
External links
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